 8/20= .4 or 40%

The question doesn't mention if the attempts are field goals, or free throws. There are actually 3 different percentages for shooting in basketball. Free throws, Field Goals, and 3 Pointers. Lets just assume that the shots are field goals. The player takes 20 shots, and 8 are made. You are correct. Completion Percentage = Shots Made/ Shots Attempted = 8/20 = 4/10 = 0.40 = 40% Since percentages are of 100. N% = n/100. If the player were to attempt 100 shots , he will make 40 of them. Because 8/20 = 40/100
by Mathman99
It's important to note here that the probability that he would score 8 out of 20 baskets is different than asking what percentage of time he actually DID score.
If you are asking what the probability of getting 8 out of 20 is, or the percentage of the probability that was actually achieved versus what we expected, we have to first know the probability of scoring each time when shooting 20 baskets.
So here you go: In terms of probability percentage using relative frequency, assuming there are no extenuating circumstances we're unaware of,
The probability that someone would score 8 out of 20 baskets (because there are 19 other equal possibilities) is 1 out of 20, (1/20), or as a percentage 5%.
But wait :)there's more. (don't roll your eyesLOL!)Some background info:
1) The probability that a shot will be a scoring one is 1/2 or 50%: The number of shots taken are independent factors (in other words, whether the person makes the second shot, etc. Is not dependent on whether he made the first shot; neither are dependent on whether the last time was a score or not). So if you're looking for the difference between what we would expect and what actually happened, then we would have expected the guy to make half or 50% of his baskets (10 out of 20, right?). But the guy/gal only made 40% of his shots (so 20 possible scores divided into 8 actual scores = .40 or 40% of possible times to score). Then the percentage of probability met in this case was: .50 (possibility of scoring) minus .40 (percentage he actually DID score) = 10%... Or .10
If you are asking what the probability of getting 8 out of 20 is, or the percentage of the probability that was actually achieved versus what we expected, we have to first know the probability of scoring each time when shooting 20 baskets.
So here you go: In terms of probability percentage using relative frequency, assuming there are no extenuating circumstances we're unaware of,
The probability that someone would score 8 out of 20 baskets (because there are 19 other equal possibilities) is 1 out of 20, (1/20), or as a percentage 5%.
But wait :)there's more. (don't roll your eyesLOL!)Some background info:
1) The probability that a shot will be a scoring one is 1/2 or 50%: The number of shots taken are independent factors (in other words, whether the person makes the second shot, etc. Is not dependent on whether he made the first shot; neither are dependent on whether the last time was a score or not). So if you're looking for the difference between what we would expect and what actually happened, then we would have expected the guy to make half or 50% of his baskets (10 out of 20, right?). But the guy/gal only made 40% of his shots (so 20 possible scores divided into 8 actual scores = .40 or 40% of possible times to score). Then the percentage of probability met in this case was: .50 (possibility of scoring) minus .40 (percentage he actually DID score) = 10%... Or .10
This all sounds like a bunch of POLITICS if you ask me......I don't think there is an actual correct answer because you have too many variables the way this question is worded....that's my story and I'm sticking with it!
Orneryone is correct. The number of completions of the number of attempts Same as an nfl quarterback. Throws 60 passes. 30 of them caught. 30/60=50%
32%
To the guest who posted 1 year ago (the long post about the probability)... Thanks :)  although you'll probably never hit this post again but if you ever do and happen to read the comment. Thanks :)